Develop Reference

Python: Button widget in Tkinter

I have just now begun with GUI programming in Python 2.7 with Tkinter.
I want to have a button Browse, which when clicked opens the Windows File Explorer and returns the path of file selected to a variable. I wish to use that path later.
I am following the code given here. It outputs a window displaying 5 buttons, but the buttons do nothing. On clicking the first button, it doesn't open the selected file.
Likewise, on clicking the second button, the askopenfilename(self) function is called and it should return a filename. Like I mentioned, I need that filename later.
How to I get the value returned by the function into some variable for future use?

There is no point in using return inside a callback to a button. It won't return to anywhere. The way to make a callback save data is to store it in a global variable, or an instance variable if you use classes.
def fetchpath():
global filename
filename = tkFileDialog.askopenfilename(initialdir = 'E:')
FWIW (and unrelated to the question): you're making a very common mistake. In python, when you do foo=bar().baz(), foo takes the value in baz(). Thus, when you do this:
button = Button(...).pack()
button will take the value of pack() which always returns None. You should separate widget creation from widget layout if you expect to save an actual reference to the widget being created. Even if you're not, it's a good practice to separate the two.

Tkinter Initial Cursor position and Enter to press button

I am making a box that is similar to the tkMessageBox. There are two simple behaviors that I want to the box to have. First I want the button to be selected automatically when the window opens, and second I want to be able to press enter to push the button. Sounds simple and I realize that I could use the tkinterMessageBox to do this same thing, but this is a stepping stone, and I would like to know how to do this in the future for other things.
The current behavior of the window below is that it opens, and if I press tab it will select the button, but then i can only press the button with the mouse. Again the desired functionality is to have the button selected right away and be able to press the button with the enter key.
import Tkinter, tkMessageBox
from Tkinter import *
def closewindow():
Messagebox.destroy()
Messagebox=Tk()
l3=Label( Messagebox, text="This is your preview! Align camera then press ESC")
b3=Button(Messagebox, text="Okay", command=closewindow)
l3.grid(row=1,column=1)
b3.grid(row=2,column=1)
Messagebox.mainloop()

You can actually do this with just two lines of code:
b3.bind('<Return>', lambda _: closewindow())
b3.focus_set()
The first binds the button to the Enter key and the second sets the application's focus on the button.
Note that I had to use a lambda with the binding to handle the event object that will be sent to the callback. You could however change the definition of closewindow to handle this:
def closewindow(event=None):
Messagebox.destroy()
Now you can just do:
b3.bind('<Return>', closewindow)
For more information on bindings in Tkinter, see Events and Bindings over on Effbot.

Tkinter add entry on basis of an answer of a OptionMenu

I'm using TKinter (I'm new with GUI tools), and I would like to know if it is possible to add (or activate) a entry with base on the answer of a option menu. Below is a part of the code
from Tkinter import *
win=Tk()
Label(win, text="Is This a Data Cube?",font='20').grid(row=14, column=0,sticky=W)
DataCubeValue = StringVar(win)
DataCubeValue.set("False")
DataCube = OptionMenu(win,DataCubeValue,"True","False")
DataCube.grid(row=15, column=0,sticky=W)
If the answer is True is choosen I would like to display this:
Label(win, text="X and Y values (x,y)",font='20').grid(row=14, column=1,sticky=W)
XYValue = StringVar(win)
XYValue.set("10,7")
XY = Entry(win,textvariable=XYValue)
XY.grid(row=15, column=1,sticky=W)

A central idea of GUI programming is to register code to be executed in reaction of user actions. Such code is usually named callback (the toolkit call it back depending on user actions on the interface).
You can bind to DataCubeValue changes with the following line. callback method (to be defined before) will be cause each time the value of DataCubeValue change.
DataCubeValue.trace("w", callback)
In the callback method, you can either choose to place the block of code with Label and Entry instantiation, but think that callback will be called every time the user change the OptionMenu value. You could either deactivate the OptionMenu once the user used it, but I would advise to instantiate your widgets in the initial run, and just display or hide them from the callback.
def callback(*args):
if DataCubeValue.get() == "True":
label.grid(row=14, column=1,sticky=W)
XY.grid(row=15, column=1,sticky=W)
else:
label.grid_forget()
XY.grid_forget()

More on passing arguments to tkinter button command

I have a number of test files in a single directory. I'm trying to write a GUI to allow me to select and run one of them.
So, I have a loop that scans the directory and creates buttons:
for fnm in glob.glob ('Run*.py'):
tstName = fnm[3:-3] # Discard fixed part of filename
btn = Button (self, text=tstName,
command=lambda: self.test(tstName))
btn.grid (row=rowNum, column=0, pady=2)
rowNum += 1
This creates my GUI correctly, with buttons labelled say, A and B but when I press on the button labelled A it passes B to the test method.
I've looked around and found this question How can I pass arguments to Tkinter button's callback command? but the answer doesn't go on to use the same variable name, with a different value, to configure another widget. (In fact, by tying the variable name to the widget name it almost implies that the technique won't work in this case, as I've found.)
I'm very new to Python, but am quite familiar with creating this kind of GUI using Tcl/TK and I recognise this problem - the value of tstName is being passed when I press the button, but I want it to pass the value the variable had when I created it. I know how I'd fix that in Tcl/Tk - I'd define a command string using [list] at creation time which would capture the value of the variable.
How do I do the same in Python?

You need to bind the current value of tstName at the time you define the button. The way you're doing it, the value of tstName will whatever it is at the time you press the button.
To bind the value at the time that you create the button, use the value of tstName as the default value of a keyword parameter to the lambda, like so:
btn = Button(..., command=lambda t=tstName: self.test(t))

getting the label value of a button in Gtk

Am learning Gtk. I wanted to build a calculator, in which i want to display the number pressed , in the textbox. I have completed it, by calling different functions for different buttons clicked, and appending the value in the textbox with the value of the button pressed. Using python 2.7.3
Is there a way to obtain the label value of the button pressed so that i can use a single function instead of 10 functions from 0 to 9?
Thanks in advance

Button callbacks include the widget itself, and you can also pass data. See here.

instead of reading the label of the GtkButton, which is pretty much error prone, you should associate the value represented by the button to the button instance itself, e.g.:
button = Gtk.Button(label='1')
button._value = 1
# add button to the container
button.connect('clicked', on_button_clicked)
button = Gtk.Button(label='2')
button._value = 2
# add button to the container
button.connect('clicked', on_button_clicked)
and then read the value from the button instance inside the signal handler, e.g.:
def on_button_clicked(button):
print 'you pressed the button of value: %d' % (button._value)
GtkWidget instances in Python are Python object, and thus behave like any other Python object.