Develop Reference

I found a span on a website that is not visible and I can't scrape it! Why?

Currently I'm trying to scrape data from a website. Therefore I'm using Selenium.
Everything is working as it should. Until I realised I have to scrape a tooltiptext.
I found already different threads on stackoverflow that are providing an answer. Anyway I did not manage to solve this issue so far.
After a few hours of frustration I realised the following:
This span has nothing to do with the tooltip I guess. Because the tooltip looks like this:
There is actually a span that I can't read. I try to read it like this:
bewertung = driver.find_elements_by_xpath('//span[#class="a-icon-alt"]')
for item in bewertung:
print(item.text)
So Selenium finds this element. But unfortunatly '.text' returns nothing. Why is it always empty ?
And what for is the span from the first screenshot ? Btw. it is not displayed at the Website as well.

Since you've mentioned Selenium finds this element, I would assume you must have print the len of bewertung list
something like
print(len(bewertung))
if this list has some element in it, you could probably use innerText
bewertung = driver.find_elements_by_xpath('//span[#class="a-icon-alt"]')
for item in bewertung:
print(item.get_attribute("innerText"))
Note that, you are using find_elements which won't throw any error instead if it does not find the element it will return an empty list.
so if you use find_element instead, it would throw the exact error.
Also, I think you've xpath for the span (Which does not appear in UI, sometime they don't appear until some actions are triggered.)
You can try to use this xpath instead:
//i[#data-hook='average-stars-rating-anywhere']//span[#data-hook='acr-average-stars-rating-text']
Something like this in code:
bewertung = driver.find_elements_by_xpath("//i[#data-hook='average-stars-rating-anywhere']//span[#data-hook='acr-average-stars-rating-text']")
for item in bewertung:
print(item.text)

PYTHON - Unable To Find Xpath Using Selenium

I have been struggling with this for a while now.
I have tried various was of finding the xpath for the following highlighted HTML
I am trying to grab the dollar value listed under the highlighted Strong tag.
Here is what my last attempt looks like below:
try:
price = browser.find_element_by_xpath(".//table[#role='presentation']")
price.find_element_by_xpath(".//tbody")
price.find_element_by_xpath(".//tr")
price.find_element_by_xpath(".//td[#align='right']")
price.find_element_by_xpath(".//strong")
print(price.get_attribute("text"))
except:
print("Unable to find element text")
I attempted to access the table and all nested elements but I am still unable to access the highlighted portion. Using .text and get_attribute('text') also does not work.
Is there another way of accessing the nested element?
Or maybe I am not using XPath as it properly should be.
I have also tried the below:
price = browser.find_element_by_xpath("/html/body/div[4]")
UPDATE:
Here is the Full Code of the Site.
The Site I am using here is www.concursolutions.com
I am attempting to automate booking a flight using selenium.
When you reach the end of the process of booking and receive the price I am unable to print out the price based on the HTML.
It may have something to do with the HTML being a java script that is executed as you proceed.

Looking at the structure of the html, you could use this xpath expression:
//div[#id="gdsfarequote"]/center/table/tbody/tr[14]/td[2]/strong

Making it work
There are a few things keeping your code from working.
price.find_element_by_xpath(...) returns a new element.
Each time, you're not saving it to use with your next query. Thus, when you finally ask it for its text, you're still asking the <table> element—not the <strong> element.
Instead, you'll need to save each found element in order to use it as the scope for the next query:
table = browser.find_element_by_xpath(".//table[#role='presentation']")
tbody = table.find_element_by_xpath(".//tbody")
tr = tbody.find_element_by_xpath(".//tr")
td = tr.find_element_by_xpath(".//td[#align='right']")
strong = td.find_element_by_xpath(".//strong")
find_element_by_* returns the first matching element.
This means your call to tbody.find_element_by_xpath(".//tr") will return the first <tr> element in the <tbody>.
Instead, it looks like you want the third:
tr = tbody.find_element_by_xpath(".//tr[3]")
Note: XPath is 1-indexed.
get_attribute(...) returns HTML element attributes.
Therefore, get_attribute("text") will return the value of the text attribute on the element.
To return the text content of the element, use element.text:
strong.text
Cleaning it up
But even with the code working, there’s more that can be done to improve it.
You often don't need to specify every intermediate element.
Unless there is some ambiguity that needs to be resolved, you can ignore the <tbody> and <td> elements entirely:
table = browser.find_element_by_xpath(".//table[#role='presentation']")
tr = table.find_element_by_xpath(".//tr[3]")
strong = tr.find_element_by_xpath(".//strong")
XPath can be overkill.
If you're just looking for an element by its tag name, you can avoid XPath entirely:
strong = tr.find_element_by_tag_name("strong")
The fare row may change.
Instead of relying on a specific position, you can scope using a text search:
tr = table.find_element_by_xpath(".//tr[contains(text(), 'Base Fare')]")
Other <table> elements may be added to the page.
If the table had some header text, you could use the same text search approach as with the <tr>.
In this case, it would probably be more meaningful to scope to the #gdsfarequite <div> rather than something as ambiguous as a <table>:
farequote = browser.find_element_by_id("gdsfarequote")
tr = farequote.find_element_by_xpath(".//tr[contains(text(), 'Base Fare')]")
But even better, capybara-py provides a nice wrapper on top of Selenium, helping to make this even simpler and clearer:
fare_quote = page.find("#gdsfarequote")
base_fare_row = fare_quote.find("tr", text="Base Fare"):
base_fare = tr.find("strong").text

XPath for LXML with Intermediary Element

I'm trying to scrape some pages with python and LXML. My test page is http://www.sarpy.com/oldterra/prop/PDisplay3.asp?ParamValue1=010558233
I'm having good luck with most of the XPaths. For example,
tree.xpath('/html/body/table/tr[1]/td[contains(text(), "Sales Information")]/../../tr[3]/td[1]/text()')
successfully gets me the date of the first sale listed. I have several other pieces too. However, I cannot get the B&P listed under the sale date. For example the B&P of the first sale is 200639333.
I notice in the page structure that there is a form element preceding the tr of the B&P item. Since it's the next table row, I tried incrementing the tr index as follows:
tree.xpath('/html/body/table/tr[1]/td[contains(text(), "Sales Information")]/../../tr[4]/td[1]/text()')
That returns:
['\r\n ']
Because of the line breaks and sub element of br and input within the field, I tried making text() into text()[1], text()[2], etc., but no luck.
I tried to base the path off of the adjacent form like this:
tree.xpath('/html/body/table[7]/form[#action="../rod/ImageDisplay.asp"]/following-sibling::tr/td[1]/text()')
No luck.
I figure there are two potential issues: the intermediary form elements that may be breaking the indexing patterns, and the whitespace. I'd appreciate any help in correcting this xpath.

The <tr> you are looking for is the child of the <form> , not its sibling , try -
tree.xpath('/html/body/table/tr[1]/td[contains(text(), "Sales Information")]/../../form[1]/td[1]/text()')
This may get you 200639333 with a lot of whitespaces.
Or -
tree.xpath('/html/body/table[7]/form[#action="../rod/ImageDisplay.asp"]/tr[1]/td[1]/text()')
For all such elements.

Scraping Text from table using Soup / Xpath / Python

I need help in extracting data from : http://agmart.in/crop.aspx?ccid=1&crpid=1&sortby=QtyHigh-Low
Using the filter, there are about 4 pages of data (Under rice crops) in tables I need to store.
I'm not quite sure how to proceed with it. been reading up all the documentation possible. For someone who just started python, I'm very confused atm. Any help is appreciated.
Here's a code snipet I'm basing it on :
Example website : http://www.uscho.com/rankings/d-i-mens-poll/
from urllib2 import urlopen
from lxml import etree
url = 'http://www.uscho.com/rankings/d-i-mens-poll/'
tree = etree.HTML(urlopen(url).read())
for section in tree.xpath('//section[#id="rankings"]'):
print section.xpath('h1[1]/text()')[0],
print section.xpath('h3[1]/text()')[0]
print
for row in section.xpath('table/tr[#class="even" or #class="odd"]'):
print '%-3s %-20s %10s %10s %10s %10s' % tuple(
''.join(col.xpath('.//text()')) for col in row.xpath('td'))
print
I can't seem to understand any of the code above. Only understood that the URL is being read. :(
Thank you for any help!

Just like we have CSS selectors like .window or #rankings, xpath is used to navigate through elements and attributes in XML.
So in for loop, you're first searching for an element called "section" give a condition that it has an attribute id whose value is rankings. But remember you are not done yet. This section also contains the heading "Final USCHO.com Division I Men's Polo", date and extra elements in the table. Well, there was only one element and this loop will run only once. That's where you're extracting the text (everything within the TAGS) in h1 (Heading) and h3 (Date).
Next part extracts a tag called table, with conditions on each row's classes - they can be even or odd. Well, because you need all the rows in this table, that part is not doing anything here.
You could replace the line
for row in section.xpath('table/tr[#class="even" or #class="odd"]'):
with
for row in section.xpath('table/tr'):
Now when we are inside the loop, it will return us each 'td' element - each cell in that row. That's why the last line says row.xpath('td'). When you iterate over them, you'll receive multiple cell elements, e.g. each for 1, Providence, 49, 26-13-2, 997, 15. Check first line in the webpage table.
Try this for yourself. Replace the last loop block with this much easier to read alternative:
for row in section.xpath('table/tr'):
print row.xpath('td//text()')
You will see that it presents all the table data in Pythonic lists - each list item containing one cell. Your code is just another fancier way to write these list items converted into a string with spaces between them. xpath() method returns objects of Element type which are representation of each XML/HTML element. xpath('something//text()') would produce the actual content within that tag.
Here're a few helpful references:
Easy to understand tutorial :
http://www.w3schools.com/xpath/xpath_examples.asp
Stackoverflow question : Extract text between tags with XPath including markup
Another tutorial : http://www.tutorialspoint.com/xpath/

[Python]Get a XPath Value from Steam and print it

I want to get an XPATH-Value from a Steamstoresite, e.g. http://store.steampowered.com/app/234160/. On the right side are 2 boxes. The first one contains Title, Genre, Developer ... I just need the Genre here. There is a different count on every game. Some have 4 Genres, some just one. And then there is another block, where the gamefeatures are listet (like Singleplayer, Multiplayer, Coop, Gamepad, ...)
I need all those values.
Also sometimes there is an image between (PEGI/USK)
http://store.steampowered.com/app/233290.
import requests
from lxml import html
page = requests.get('http://store.steampowered.com/app/234160/')
tree = html.fromstring(page.text)
blockone = tree.xpath(".//*[#id='main_content']/div[4]/div[3]/div[2]/div/div[1]")
blocktwo = tree.xpath(".//*[#id='main_content']/div[4]/div[3]/div[2]/div/div[2]")
print "Detailblock:" , blockone
print "Featureblock:" , blocktwo
This is the code I have so far. When I try it it just prints:
Detailblock: [<Element div at 0x2ce5868>]
Featureblock: [<Element div at 0x2ce58b8>]
How do I make this work?

xpath returns a list of matching elements. You're just printing out that list.
If you want the first element, you need blockone[0]. If you want all elements, you have to loop over them (e.g., with a comprehension).
And meanwhile, what do you want to print for each element? The direct inner text? The HTML for the whole subtree rooted at that element? Something else? Whatever you want, you need to use the appropriate method on the Element type to get it; lxml can't read your mind and figure out what you want, and neither can we.
It sounds like what you really want is just some elements deeper in the tree. You could xpath your way there. (Instead of going through all of the elements one by one and relying on index as you did, I'm just going to write the simplest way to get to what I think you're asking for.)
genres = [a.text for a in blockone[0].xpath('.//a')]
Or, really, why even get that blockone in the first place? Why not just xpath directly to the elements you wanted in the first place?
gtags = tree.xpath(".//*[#id='main_content']/div[4]/div[3]/div[2]/div/div[1]//a")
genres = [a.text for a in gtags]
Also, you could make this a lot simpler—and a lot more robust—if you used the information in the tags instead of finding them by explicitly walking the structure:
gtags = tree.xpath(".//div[#class='glance_tags popular_tags']//a")
Or, since there don't seem to be any other app_tag items anywhere, just:
gtags = tree.xpath(".//a[#class='app_tag']")