Ok, so I am looking for an algorithm that can calculate the boundaries of two 'splashes' that are depicte on the following graph. This is the graph. We can observe here two 'splashes' in the middle
So I was trying to solve this with the derivative but it only worked when there is one splash, not two or more. If you worked with time-series or just know how to find the asnwer, please, feel free to write below. Thank you in advance!
One approach would be to move two points along a line with a small horizontal offset between them. You can use these points to calculate local slope, and when the slope exceeds a threshold, mark the location between the points as a "boundary" by adding it to a boundary list.
I have a bunch of noisy data.
I need be able to find the points where the increase in y begins and ends. Visually it's pretty obvious, but i've been having a hard time trying to come up with an algorithm that would be consistent and accurate.
I tried getting the slope directly (just as a difference of neighboring points):
But here still, i'm not sure how to properly identify the beginning and end of a step. I tried just going off of the magnitude of difference between points, but I get either a lot of false positives (like in that very noisy spike in the second graph), or I miss the very small steps (like the first and third). I also tried going in steps of ten points, calculating a best fit line, and the MSE, and when the MSE gets about a certain threshold, i would consider that a corner in the graph. For example, for 10 points in the somewhat horizontal line, the MSE for the best fit line would be small, but for 9 points and 1 that is at the beginning of the incline, the MSE is much larger.
I thought about trying to convert it into a step graph, but I'm not sure how to do it, plus i feel like i might end up with just one point where the graph goes from low to high, rather than two points, one for when it starts increasing, and another when it stops.
Does anyone have any ideas on how one might go about doing this?
I am trying to reduce the number of data points for a 3D curve, currently I have 20000 points and I would like to reduce this to around 2000 without losing much information.
I am doing this on python.
As a simple example, think of a spiral on the surface of a cylinder.
Are there any built-in functions that will do this?
I've tried using the Ramer–Douglas–Peucker algorithm to simplify the line, but due to the nature of the curve, for every data point ignored the final plot is undershooting. See picture of a 2D example, orange is what using rdp produces, green is what I want.
I would like the output of the program to be an array of ~2000 coordinates that still represent the shape of the 3D curve but they don't necessarily have to be original coordinates, I want some points to overshoot and others to undershoot.
Thank you for your help
UPDATE:
In the end I chose to do something quite involved but gave me exactly what I wanted. I started using the rdp algorithm to reduce the number of points. With this new information I then fit a straight line of best fit to the spread of the original points between the new reduced points:
i.e. if the algorithm 'ignored' 13 points, I fit the line from point 0 to point 14, and did the same for the next segment where the algorithm had skipped for example 7 points, so I fit from 14 to 22 etc.
Having those lines of best fit, I found the points were the lines intersected or if the lines did not intersect, the closest point on each of the lines to the other line.
Due to the nature of my problem, I did not need my data to be continuous, so 2000 "discontinuous" segments were not a problem.
Thank you very much for your help!
In the end I chose to do something quite involved but gave me exactly what I wanted. I started using the rdp algorithm to reduce the number of points. With this new information I then fit a straight line of best fit to the spread of the original points between the new reduced points: i.e. if the algorithm 'ignored' 13 points, I fit the line from point 0 to point 14, and did the same for the next segment where the algorithm had skipped for example 7 points, so I fit from 14 to 22 etc. Having those lines of best fit, I found the points were the lines intersected or if the lines did not intersect, the closest point on each of the lines to the other line. Due to the nature of my problem, I did not need my data to be continuous, so 2000 "discontinuous" segments were not a problem. Thank you very much for your help!
I have images of ore seams which I have first skeletonised (medial axis multiplied by the distance transform), then extracted corners (see the green dots). It looks like this:
The problem is to find a turning point and then segment the seam by separating the seam at the turning point. Not all skeletons have turning points, some are quite linear, and the turning points can be in any orientation. But the above image shows a seam which does have a defined turning point. Other examples of turning points look like (using ASCII): "- /- _". "X" turning points don't really exist.
I've tried a number of methods including downsampling the image, curve fitting, k-means clustering, corner detection at various thresholds and window sizes, and I haven't figured it out yet. (I'm new to to using scikit)
The technique must be able to give me some value which I can use heuristically determine whether there is a turning point or not.
What I'd like to do is to do some sort of 2 line ("piecewise"?) regression and find an intersection or some sort of rotated polynomial regression, then determine if a turning point exists, and if it does exist, the best coordinate that represents the turning point. Here is my work in progress: https://gist.github.com/anonymous/40eda19e50dec671126a
From there, I learned that a watershed segmentation with appropriate label coordinates should be able to segment the skeleton.
I found this resource: Fit a curve for data made up of two distinct regimes
But I wasn't able to figure out to apply it my current situation. More importantly there's no way for me to guess a-priori what the initial coefficients are for the fitting function since the skeletons can be in any orientation.
I have a large collection of rectangles, all of the same size. I am generating random points that should not fall in these rectangles, so what I wish to do is test if the generated point lies in one of the rectangles, and if it does, generate a new point.
Using R-trees seem to work, but they are really meant for rectangles and not points. I could use a modified version of a R-tree algorithm which works with points too, but I'd rather not reinvent the wheel, if there is already some better solution. I'm not very familiar with data-structures, so maybe there already exists some structure that works for my problem?
In summary, basically what I'm asking is if anyone knows of a good algorithm, that works in Python, that can be used to check if a point lies in any rectangle in a given set of rectangles.
edit: This is in 2D and the rectangles are not rotated.
This Reddit thread addresses your problem:
I have a set of rectangles, and need to determine whether a point is contained within any of them. What are some good data structures to do this, with fast lookup being important?
If your universe is integer, or if the level of precision is well known and is not too high, you can use abelsson's suggestion from the thread, using O(1) lookup using coloring:
As usual you can trade space for
time.. here is a O(1) lookup with very
low constant. init: Create a bitmap
large enough to envelop all rectangles
with sufficient precision, initialize
it to black. Color all pixels
containing any rectangle white. O(1)
lookup: is the point (x,y) white? If
so, a rectangle was hit.
I recommend you go to that post and fully read ModernRonin's answer which is the most accepted one. I pasted it here:
First, the micro problem. You have an
arbitrarily rotated rectangle, and a
point. Is the point inside the
rectangle?
There are many ways to do this. But
the best, I think, is using the 2d
vector cross product. First, make sure
the points of the rectangle are stored
in clockwise order. Then do the vector
cross product with 1) the vector
formed by the two points of the side
and 2) a vector from the first point
of the side to the test point. Check
the sign of the result - positive is
inside (to the right of) the side,
negative is outside. If it's inside
all four sides, it's inside the
rectangle. Or equivalently, if it's
outside any of the sides, it's outside
the rectangle. More explanation here.
This method will take 3 subtracts per
vector * times 2 vectors per side,
plus one cross product per side which
is three multiplies and two adds. 11
flops per side, 44 flops per
rectangle.
If you don't like the cross product,
then you could do something like:
figure out the inscribed and
circumscribed circles for each
rectangle, check if the point inside
the inscribed one. If so, it's in the
rectangle as well. If not, check if
it's outside the circumscribed
rectangle. If so, it's outside the
rectangle as well. If it falls between
the two circles, you're f****d and you
have to check it the hard way.
Finding if a point is inside a circle
in 2d takes two subtractions and two
squarings (= multiplies), and then you
compare distance squared to avoid
having to do a square root. That's 4
flops, times two circles is 8 flops -
but sometimes you still won't know.
Also this assumes that you don't pay
any CPU time to compute the
circumscribed or inscribed circles,
which may or may not be true depending
on how much pre-computation you're
willing to do on your rectangle set.
In any event, it's probably not a
great idea to test the point against
every rectangle, especially if you
have a hundred million of them.
Which brings us to the macro problem.
How to avoid testing the point against
every single rectangle in the set? In
2D, this is probably a quad-tree
problem. In 3d, what generic_handle
said - an octree. Off the top of my
head, I would probably implement it as
a B+ tree. It's tempting to use d = 5,
so that each node can have up to 4
children, since that maps so nicely
onto the quad-tree abstraction. But if
the set of rectangles is too big to
fit into main memory (not very likely
these days), then having nodes the
same size as disk blocks is probably
the way to go.
Watch out for annoying degenerate
cases, like some data set that has ten
thousand nearly identical rectangles
with centers at the same exact point.
:P
Why is this problem important? It's
useful in computer graphics, to check
if a ray intersects a polygon. I.e.,
did that sniper rifle shot you just
made hit the person you were shooting
at? It's also used in real-time map
software, like say GPS units. GPS
tells you the coordinates you're at,
but the map software has to find where
that point is in a huge amount of map
data, and do it several times per
second.
Again, credit to ModernRonin...
For rectangles that are aligned with the axes, you only need two points (four numbers) to identify the rectangle - conventionally, bottom-left and top-right corners. To establish whether a given point (Xtest, Ytest) overlaps with a rectangle (XBL, YBL, XTR, YTR) by testing both:
Xtest >= XBL && Xtest <= XTR
Ytest >= YBL && Ytest <= YTR
Clearly, for a large enough set of points to test, this could be fairly time consuming. The question, then, is how to optimize the testing.
Clearly, one optimization is to establish the minimum and maximum X and Y values for the box surrounding all the rectangles (the bounding box): a swift test on this shows whether there is any need to look further.
Xtest >= Xmin && Xtest <= Xmax
Ytest >= Ymin && Ytest <= Ymax
Depending on how much of the total surface area is covered with rectangles, you might be able to find non-overlapping sub-areas that contain rectangles, and you could then avoid searching those sub-areas that cannot contain a rectangle overlapping the point, again saving comparisons during the search at the cost of pre-computation of suitable data structures. If the set of rectangles is sparse enough, there may be no overlapping, in which case this degenerates into the brute-force search. Equally, if the set of rectangles is so dense that there are no sub-ranges in the bounding box that can be split up without breaking rectangles.
However, you could also arbitrarily break up the bounding area into, say, quarters (half in each direction). You would then use a list of boxes which would include more boxes than in the original set (two or four boxes for each box that overlapped one of the arbitrary boundaries). The advantage of this is that you could then eliminate three of the four quarters from the search, reducing the amount of searching to be done in total - at the expense of auxilliary storage.
So, there are space-time trade-offs, as ever. And pre-computation versus search trade-offs. If you are unlucky, the pre-computation achieves nothing (for example, there are two boxes only, and they don't overlap on either axis). On the other hand, it could achieve considerable search-time benefit.
I suggest you take a look at BSP trees (and possible quadtrees or octrees, links available on that page as well). They are used to partition the whole space recursively and allow you to quickly check for a point which rectangles you need to check at all.
At minimum you just have one huge partition and need to check all rectangles, at maximum your partitions get so small, that they get down to the size of single rectangles. Of course the more fine-grained the partition, the longer you need to walk down the tree in order to find the rectangles you want to check.
However, you can freely decide how many rectangles are suitable to be checked for a point and then create the corresponding structure.
Pay attention to overlapping rectangles though. As the BSP tree needs to be precomputed anyways, you may as well remove overlaps during that time, so you can get clear partitions.
Your R-tree approach is the best approach I know of (that's the approach I would choose over quadtrees, B+ trees, or BSP trees, as R-trees seem convenient to build in your case). Caveat: I'm no expert, even though I remember a few things from my senior year university class of algorithmic!
Why not try this. It seems rather light on both computation and memory.
Consider the projections of all the rectangles onto the base line of your space. Denote that set of line intervals as
{[Rl1, Rr1], [Rl2, Rr2],..., [Rln, Rrn]}, ordered by increasing left coordinates.
Now suppose your point is (x, y), start a search at the left of this set until you reach a line interval that contains the point x.
If none does, your point (x,y) is outside all rectangles.
If some do, say [Rlk, Rrk], ..., [Rlh, Rrh], (k <= h) then just check whether y is within the vertical extent of any of these rectangles.
Done.
Good luck.
John Doner