I am creating a Yahzee game, and I want it to save a 'dice' roll, temporarily.
import random
roll = random.randint(0, 6)
print("Dice 1: " + roll)
print("Dice 2: " + roll)
input = "Save die?"
if input == "Dice 2":
print("Dice 1: " + roll)
# Print Dice 2's number above, below
It should output:
Dice 1: 3
Dice 2: 6
Save Die? Die 2
Dice 1: 2
Dice 2: 6
How do I make it save the number, so I can use it, but then after 6 moves, 5 Rolls and choosing the play, it will erase.
I do not know what is a Yahzee game, but I think you need a simple data structure like list to save your results and empty the list when it is necessary.
import random
results = []
move_num = 6
while True:
for i in range(move_num):
dices = [random.randint(0, 6), random.randint(0, 6)]
print('Dice 1: {}'.format(dices[0]))
print('Dice 2: {}'.format(dices[1]))
decision = int(input('Save die?'))
if decision in [1, 2]:
results.append(dices[decision-1])
else:
print('wrong dice number')
print('results are {}'.format(results))
results.clear()
I do not understand the game rules, hope this could help you.
Related
Im trying to make a loop where I start with 5 random dice rolls. the values 1,3,4, and 6 are added up for your score, while 2s and 5s are not counted and subtract the combined amount of dice rolled with 2s and 5s from the amount of dice rolled the next turn. I can't quite figure out how to get the sum of only the dice that rolled 1,3,4,6 and roll a lesser amount of dice the next turn based off ho many dice were 2 or 5
#Stuck in the Mud Dice Game
Exit = 0
Rolls = int(5)
score = 0
def RollDice():
totalsum = 0
for die in range(0, Rolls):
number = random.randint(1,6)
print("die", die + 1, ":", number)
totalsum += number
print("score: ", totalsum)
def Menu():
print("1. Roll Dice")
print("2. Exit Program")
print()
choice = int(input("Enter option here: "))
if(choice == 1):
RollDice()
if(choice == 2):
Exit()
Menu()
In the for-loop, use an if statement:
if number==2 or number==5:
Rolls -= 1
else:
totalsum += number
I suppose that you also need to start your function RollDice like this:
def RollDice():
global Rolls
...
otherwise, it might only locally (i.e., within the function) assign a new value to the variable.
Or do you mean the number of Rolls should be different when you re-start the program? This can only be done by writing the value to a file.
I need help condensing my Yahtzee code. I'm familiar with loops, but I can't seem to figure out how to do it without wiping my roll each turn. It's set up to roll 5 random dice and then you choose which you want to keep. It will then roll what's left for three total rolls. I thought of making a placeholder list, but I can't make it work that way either.
Dice = [‘⚀ ’,‘⚁ ‘,’ ⚂ ‘,’ ⚃ ‘,’ ⚄ ‘,’ ⚅ ‘]
turns = 3
#first roll
first_roll = []
for _ in range(5):
roll = random.choice(dice)
first_roll.append(roll)
print(first_roll)
turns -= 1
print(f'You have {turns} turns left.')
keep = input("Which dice would you like to keep? 1 - 5: ").split()
clear()
#second roll
second_roll = []
for i in keep:
x = int(i)
j = first_roll[x-1]
second_roll.append(j)
remainder = 5 - len(second_roll)
for _ in range(remainder):
roll = random.choice(dice)
second_roll.append(roll)
print(second_roll)
turns -= 1
print(f'This is your last turn.')
keep = input("Which dice would you like to keep? 1 - 5: ").split()
clear()
#third roll
third_roll = []
for i in keep:
x = int(i)
j = second_roll[x-1]
third_roll.append(j)
remainder = 5 - len(third_roll)
for _ in range(remainder):
roll = random.choice(dice)
third_roll.append(roll)
print(third_roll)
So I'm not sure if this is exactly what you're looking for, but I created a function that lets you continuously roll for X turns and the dice pool gets progressively smaller like your code shows. I thoroughly commented the code to hopefully give you a good explanation to what I'm doing.
import random
#Dice characters
dice = ['1','2','3','4','5','6']
#Number of turns player has
turns = 3
#This is the group of dice kept by the player
kept_dice = []
def roll():
#This is the group of dice randomly chosen
rolled_dice = []
#Generate up to 5 random dice based on how many have been kept so far
for _ in range(5 - len(kept_dice)):
#Append random dice value to rolled_dice array
rolled_dice.append(random.choice(dice))
#Print roll group
print(rolled_dice)
dice_to_keep = int(input("Which dice would you like to keep? 1 - 5: "))
kept_dice.append(rolled_dice[dice_to_keep-1])
while turns != 0:
#Let the user know how many turns they have left
print(f'You have {turns} turns left.')
#Roll dice
roll()
#Subtract 1 turn
turns -= 1
#After all turns, show the kept dice:
print("Kept dice:")
print(kept_dice)
I am working on dice rolling game which prints out the number of attempts (n) before both dice shows the same value.
I would like to also print out the past rolling results. However, my code only shows the last rolling results (n-1 attempts).
I have tried to google and check the past history of stackoverflow dice rolling queries and I still can't figure out how to solve the code. Please help, I think it has got to do with nested list or dictionaries, but I just can't figure it out.
Below is my code:
from random import randint
stop = 0
count = 0
record = []
while stop == 0:
roll = [(dice1, dice2) for i in range(count)]
dice1 = randint(1,6)
dice2 = randint(1,6)
if dice1 != dice2:
count += 1
else:
stop += 1
record.append(roll)
if count == 0 and stop == 1:
print("You roll same number for both dice at first try!")
else:
print(f"You roll same number for both dice after {count+1} attempts.")
print("The past record of dice rolling as below: ")
print(record)
You have a few mistakes in your code. The first, is that I'm not entirely sure what the
roll = [(dice1, dice2) for i in range(count)]
line is doing for you.
You can make a few simple changes though.
First - your record.append(...) line is outside of your loop. That is why you only see the previous run. It's only recording one run.
Second, your while statement can be a simple while True: with a break in it when you meet your matching condition. You don't need the stop variable.
from random import randint
count = 0
record = []
while True:
dice1 = randint(1,6)
dice2 = randint(1,6)
record.append([dice1,dice2])
if dice1 != dice2:
count += 1
else:
break
if count == 0:
print("You roll same number for both dice at first try!")
else:
print(f"You roll same number for both dice after {count+1} attempts.")
print("The past record of dice rolling as below: ")
print(record)
With output similar to this:
You roll same number for both dice after 8 attempts.
The past record of dice rolling as below:
[[1, 6], [2, 1], [1, 6], [5, 6], [5, 3], [6, 3], [6, 5], [4, 4]]
Notice that I've brought the .append(...) into your while loop. I've also made the changes around the stop variable as I described.
I would do something similar to #TeleNoob. Just use while True: and break when the condition is met.
Here's my reworking:
from random import randint
roll = 0
die1_record = []
die2_record = []
while True:
die1 = randint(1,6)
die2 = randint(1,6)
die1_record.append(die1)
die2_record.append(die2)
roll += 1
if die1 == die2:
break
print(f"You rolled same number for both dice after {roll} attempt(s).")
print("The past record of dice rolling is: ")
print(f"die1: {die1_record}")
print(f"die2: {die2_record}")
import random
total = [0]
one = 0
two = 0
three = 0
four = 0
five = 0
six = 0
dice=True
while dice:
a = random.randrange(1,7)
if a == 1:
one = one + 1
elif a == 2:
two = two + 1
elif a == 3:
three = three + 1
elif a == 4:
four = four + 1
elif a == 5:
five = five + 1
elif a == 6:
six = six + 1
b = len(total)
print ("Roll:", b,)
print ("The dice has rolled:",a,)
total.append (a)
dice =input("Roll again? (y,n):")
if dice == "n":
print ("Thank-You!")
print ("One rolled",one,"times")
print ("Two rolled",two,"times")
print ("Three rolled",three,"times")
print ("Four rolled",four,"times")
print ("Five rolled",five,"times")
print ("Six rolled",six,"times")
break
How can I make it so that if "one" has only been rolled "once" it says "one has been rolled time" instead of "one has been rolled 1 times"?
Thanks. An explanation would also be good so that I can learn
Make a function called printTimesRolled or something similar. Then pass a string, and an int. Like this:
def printTimesRolled(numberWord, timesRolled):
if (timesRolled == 1):
print(numberWord, "rolled 1 time.")
else:
print(numberWord, "rolled", timesRolled, "times.")
Then, to print them all, just do this:
printTimesRolled("One", one)
printTimesRolled("Two", two)
...
You can use str.format and a check whether the number has been rolled exactly one time. Demo:
>>> one = 1
>>> 'One rolled {} time{}'.format(one, 's' if one!=1 else '')
'One rolled 1 time'
>>> one = 0
>>> 'One rolled {} time{}'.format(one, 's' if one!=1 else '')
'One rolled 0 times'
>>> one = 3
>>> 'One rolled {} time{}'.format(one, 's' if one!=1 else '')
'One rolled 3 times'
This would be a good way to handle the dice rolling. I am not sure if you have started exploring classes yet, but by making the DiceRoller class you make it slightly more organized. Besides, you avoid tons of global variables.
Using a dictionary for comparisons will allow you to run a for loop to compare it, rahter than having 6 elif statements, making the code more efficient.
Finally, when the user types "n" to quit and check on his rolls, we compare to again.lower() to failsafe it in case the user types "N" instead.
Then it loops through the dictionary and prints 'time / roll' or 'times / rolls' based on a simple if statement.
I hope this makes sense to you, if not just ask!
import random
# DEFINING THE CLASS
class DiceRoller(object):
def __init__(self):
self.sides = {1:0,
2:0,
3:0,
4:0,
5:0,
6:0}
# WILL ROLL THE DICE AND ADD 1 TO THE SIDE COUNTER WHEN A SIDE IS ROLLED
def rollTheDice(self):
roll = random.randint(1,6)
for side in (self.sides):
if roll == side:
self.sides[side] += 1
print('Rolled a %s' % (roll))
# WILL PRINT TOTAL ROLLS WHEN CALLED
def getTotals(self):
for i, side in enumerate(self.sides):
if self.sides[side] == 1:
print('Side %s: %s roll' % (i + 1, self.sides[side]))
else:
print('Side %s: %s rolls' % (i + 1, self.sides[side]))
# THIS CODE IS EXECUTED
Dice = DiceRoller()
while True:
Dice.rollTheDice()
again = input('Roll again [y/n]: ')
if again.lower() == 'n':
break
Dice.getTotals()
This code outputs the following when run a couple of times:
Rolled a 2
Roll again [y/n]: y
Rolled a 4
Roll again [y/n]: y
Rolled a 3
Roll again [y/n]: y
Rolled a 1
Roll again [y/n]: y
Rolled a 4
Roll again [y/n]: y
Rolled a 2
Roll again [y/n]: n
Side 1: 1 roll
Side 2: 2 rolls
Side 3: 1 roll
Side 4: 2 rolls
Side 5: 0 rolls
Side 6: 0 rolls
Process finished with exit code 0
So I had to make code that roll a die fairly and counted how many 4's I got. With the help of people on here I got it to work. Well now I have to created another die and roll them and then add they products together. This is the instructions I've been given.
"Then write another function that simulates rolling two fair dice. The easy way is to call the function you just wrote, twice, and add the numbers you get.
This should return a number between 2 and 12."
I've added rolling the dice a second time but how do I add the sums of the two rolls together is my question?
And this is my code.
from random import randrange
def roll():
rolled = randrange(1,7)
if rolled == 1:
return "1"
if rolled == 2:
return "2"
if rolled == 3:
return "3"
if rolled == 4:
return "4"
if rolled == 5:
return "5"
if rolled == 6:
return "6"
def rollManyCountTwo(n):
twoCount = 0
for i in range (n):
if roll() == "2":
twoCount += 1
if roll() == "2":
twoCount +=1
print ("In", n,"rolls of a pair of dice, there were",twoCount,"twos.")
rollManyCountTwo(6000)
You shouldn't have to deal with strings at all, this could be done entirely using int values
from random import randint
def roll():
return randint(1,6)
def roll_twice():
total = 0
for turn in range(2):
total += roll()
return total
For example
>>> roll_twice()
10
>>> roll_twice()
7
>>> roll_twice()
8
And for your function that is supposed to count the number of 2s that were rolled, again you can do integer comparison
def rollManyCountTwo(n):
twos = 0
for turn in range(n):
if roll() == 2:
twos += 1
print('In {} rolls of a pair of dice there were {} twos'.format(n, twos))
return twos
>>> rollManyCountTwo(600)
In 600 rolls of a pair of dice there were 85 twos
85
from random import randint
def roll():
return randint(1,6)
def rollManyCountTwo(n):
twoCount = 0
for _n in xrange(n*2):
if roll() == 2:
twoCount += 1
print "In {n} rolls of a pair of dice, there were {cnt} twos.".format(n=n, cnt=twoCount)
Since you roll two dices for n times and count every single two rolled, just loop for n*2 and check if the dice result is two.