Please help I need python to compare text line(s) to words like this.
with open('textfile', 'r') as f:
contents = f.readlines()
print(f_contents)
if f_contents=="a":
print("text")
I also would need it to, read a certain line, and compare that line. But when I run this program it does not do anything no error messages, nor does it print text. Also
How do you get python to write in just line 1? When I try to do it for some reason, it combines both words together can someone help thank you!
what is f_contents it's supposed to be just print(contents)after reading in each line and storing it to contents. Hope that helps :)
An example of reading a file content:
with open("criticaldocuments.txt", "r") as f:
for line in f:
print(line)
#prints all the lines in this file
#allows the user to iterate over the file line by line
OR what you want is something like this using readlines():
with open("criticaldocuments.txt", "r") as f:
contents = f.readlines()
#readlines() will store each and every line into var contents
if contents == None:
print("No lines were stored, file execution failed most likely")
elif contents == "Password is Password":
print("We cracked it")
else:
print(contents)
# this returns all the lines if no matches
Note:
contents = f.readlines()
Can be done like this too:
for line in f.readlines():
#this eliminates the ambiguity of what 'contents' is doing
#and you could work through the rest of the code the same way except
#replace the contents with 'line'.
Related
I have a set of placemarks, which include quite a wide description included in its balloon within the property. Next each single description (former column header) is bounded in . Because of the shapefile naming restriction to 10 characters only.
https://gis.stackexchange.com/questions/15784/bypassing-10-character-limit-of-field-name-in-shapefiles
I have to retype most of these names manually.
Obviously, I use Notepad++, where I can swiftly press Ctrl+F and toggle Replace mode, as you can see below.
The green bounded strings were already replaced, the red ones still remain.
Basically, if I press "Replace All" then it works fine and quickly. Unfortunately, I have to go one by one. As you can see I have around 20 separate strings to "Replace all". Is there a possibility to do it quicker? Because all the .kml files are similar to each other, this is going to be the same everywhere. I need some tool, which will be able to do auto-replace for these headers cut by 10 characters limit. I think, that maybe Python tools might be helpful.
https://pythonhosted.org/pykml/
But in the tool above there is no information about bulk KML editing.
How can I set something like the "Replace All" tool for all my strings preferably if possible?
UPDATE:
I tried the code below:
files = []
with open("YesNF016.kml") as f:
for line in f.readlines():
if line[-1] == '\n':
files.append(line[:-1])
else:
files.append(line)
old_expression = 'ab'
new_expression = 'it worked'
for file in files:
new_file = ""
with open(file) as f:
for line in f.readlines():
new_file += line.replace(old_expression, new_expression)
with open(file, 'w') as f:
f.write(new_file)
The debugger shows:
[Errno 22] Invalid argument: ''
File "\test.py", line 13, in
with open(file) as f:
whereas line 13 is:
with open(file) as f:
The solutions here:
https://www.reddit.com/r/learnpython/comments/b9cljd/oserror_while_using_elementtree_to_parse_simple/
and
OSError: [Errno 22] Invalid argument Getting invalid argument while parsing xml in python
weren't helpful enough for me.
So you want to replace all occurence of X to Y in bunch of files ?
Pretty easy.
Just create a file_list.txt containing the list of files to edit.
python code:
files = []
with open("file_list.txt") as f:
for line in f.readlines():
if line[-1] == '\n':
files.append(line[:-1])
else:
files.append(line)
old_expression = 'ab'
new_expression = 'it worked'
for file in files:
new_file = ""
with open(file) as f:
for line in f.readlines():
new_file += line.replace(old_expression, new_expression)
with open(file, 'w') as f:
f.write(new_file)
I have a python program that is supposed to search a text file for an ID. If the Id doesn't exist in the file then the program will write it to the file.
path = "M:\\Program\\files\\"
files = [f for f in os.listdir(path) if os.path.isfile(os.path.join(path, f))]
for x in range(0, len(files)):
file = files[x]
file = file.split('`')
postid = file[0]
print(postid)
with open('postid.txt', 'r+') as f:
if postid in f:
print('already used')
else:
print('not used')
f.write(postid + '\r')
The code always returns that the string isn't in the file when It is. I have tried different methods of scanning the file such as using a for loop and examining each line but they haven't worked. I feel like I am missing some small detail but I cant find what I have done wrong.
The file looks like
1k2kk
302kk
2ll3d
2ll32
33lld
ect..
EDIT:
Never found out why the code wasn't working. I tried every suggestion but nothing worked. Finally gave up trying to read directly from the file and just had the program dump the file into a list and search the list for the ID instead of the file. I know this is not ideal but the ID file will probably not be very big when using the program so hopefully this will not cause issues.
Try a+ as the access mode.
with open('postid.txt', 'a+') as f:
You need to search the file line by line (or chunk by chunk but line by line is easiest):
with open('postid.txt', 'r+') as f:
for line in f.readlines():
if postid in line:
print("already used")
break
else:
print("not used")
f.write(postid + '\r')
I refactored your code, although I'm not sure how to name some of the variables.
for curr_str in files:
postid = curr_str.split('`')[0]
print(postid)
with open('postid.txt', 'a+') as f:
for line in f:
line = line.rstrip()
if postid == line:
print('found')
break
else:
print('not found')
f.write(postid)
def codeOnly (file):
'''Opens a file and prints the content excluding anything with a hash in it'''
f = open('boring.txt','r')
codecontent = f.read()
print(codecontent)
codeOnly('boring.txt')
I want to open this file and print the contents of it however i don't want to print any lines with hashes in them. Is there a function to prevent these lines from being printed?
The following script with print all lines which do not contain a #:
def codeOnly(file):
'''Opens a file and prints the content excluding anything with a hash in it'''
with open(file, 'r') as f_input:
for line in f_input:
if '#' not in line:
print(line, end='')
codeOnly('boring.txt')
Using with will ensure that the file is automatically closed afterwards.
You can check if the line contains a hash with not '#' in codecontent (using in):
def codeOnly (file):
'''Opens a file and prints the content excluding anything with a hash in it'''
f = open('boring.txt','r')
for line in f:
if not '#' in line:
print(line)
codeOnly('boring.txt')
If you really want to keep only code lines, you might want to keep the part of the line until the hash, because in languages such as python you could have code before the hash, for example:
print("test") # comments
You can find the index
for line in f:
try:
i = line.index('#')
line = line[:i]
except ValueError:
pass # don't change line
Now each of your lines will contain no text from and including the hash tag until the end of the line. Hash tags in the first position of a line will result in an empty string, you might want to handle that.
I am a novice with Python I suppose, and I was wondering if there was a way to read a file and then check if user's input equalled that file's text.
I've been trying to create a password program without having to show the password/variable in the program. If there's another way to do this without doing .read() and things (if they don't work) then I would be happy to hear those suggestions!
This should do it:
# The path to the file
filepath = 'thefile.txt'
# This is how you should open files
with open(filepath, 'r') as f:
# Get the entire contents of the file
file_contents = f.read()
# Remove any whitespace at the end, e.g. a newline
file_contents = file_contents.strip()
# Get the user's input
user_input = input('Enter input: ')
if user_input == file_contents:
print('Match!')
else:
print('No match.')
I should preface that I am a complete Python Newbie.
Im trying to create a script that will loop through a directory and its subdirectories looking for text files. When it encounters a text file it will parse the file and convert it to NITF XML and upload to an FTP directory.
At this point I am still working on reading the text file into variables so that they can be inserted into the XML document in the right places. An example to the text file is as follows.
Headline
Subhead
By A person
Paragraph text.
And here is the code I have so far:
with open("path/to/textFile.txt") as f:
#content = f.readlines()
head,sub,auth = [f.readline().strip() for i in range(3)]
data=f.read()
pth = os.getcwd()
print head,sub,auth,data,pth
My question is: how do I iterate through the body of the text file(data) and wrap each line in HTML P tags? For example;
<P>line of text in file </P> <P>Next line in text file</p>.
Something like
output_format = '<p>{}</p>\n'.format
with open('input') as fin, open('output', 'w') as fout:
fout.writelines( output_format(line.strip()) for line in fin )
This assumes that you want to write the new content back to the original file:
with open('path/to/textFile.txt') as f:
content = f.readlines()
with open('path/to/textFile.txt', 'w') as f:
for line in content:
f.write('<p>' + line.strip() + '</p>\n')
with open('infile') as fin, open('outfile',w) as fout:
for line in fin:
fout.write('<P>{0}</P>\n'.format(line[:-1]) #slice off the newline. Same as `line.rstrip('\n')`.
#Only do this once you're sure the script works :)
shutil.move('outfile','infile') #Need to replace the input file with the output file
in you case, you should probably replace
data=f.read()
with:
data = '\n'.join("<p>%s</p>" % l.strip() for l in f)
use data=f.readlines() here,
and then iterate over data and try something like this:
for line in data:
line="<p>"+line.strip()+"</p>"
#write line+'\n' to a file or do something else
append the and <\p> for each line
ex:
data_new=[]
data=f.readlines()
for lines in data:
data_new.append("<p>%s</p>\n" % data.strip().strip("\n"))
You could use the fileinput module to modify one or more files in-place, with optional backup file creation if desired (see its documentation for details). Here's it being used to process one file.
import fileinput
for line in fileinput.input('testinput.txt', inplace=1):
print '<P>'+line[:-1]+'<\P>'
The 'testinput.txt' argument could also be a sequence of two or more file names instead of just a single one, which could be useful especially if you're using os.walk() to generate the list of files in the directory and its subdirectories to process (as you probably should be doing).