I am learning Python through 'Automate the Boring Stuff With Python' First Edition. In chapter 12, pg 267, we are supposed to open a file called example.xlsx.
The author's code reads:
import openpyxl
wb = openpyxl.load_workbook('example.xlsx')
type(wb)
However, when I try to open this file, I get the following error (this is the last line of the error):
FileNotFoundError: [Errno 2] No such file or directory: 'example.xlsx'
I know this file exists, because I downloaded it myself and am looking at it right now.
I have tried moving it to the current location in which Python 3.8 is, I have tried saving it with my Automate the Boring Stuff files that I've been working on the desktop, and I have tried saving it in every conceivable location on my machine, but I continue getting this same message.
I have imported openpyxl without error, but when I enter the line
wb = openpyxl.load_workbook('example.xlsx')
I have entered the entire pathway for the example.xlsx in the parenthesis, and I continue to get the same error.
What am I doing wrong? How am I supposed to open an Excel workbook?
I still don't understand how I am doing wrong, but this one is incredibly infuriating, and I feel incredibly stupid, because it must be something simple.
Any insight/help is greatly appreciated.
Your error is unambigous — your file in a supposed directory don't exist. Believe me.
For Python is irrelevant, whether you see it. Python itself must see it.
Specify the full path, using forward slashes, for example:
wb = openpyxl.load_workbook('C:/users/John/example.xlsx')
Or find out your real current (working) directory — and not the one supposed by you — with commands
import os
print(os.getcwd())
then move your example.xlsx to it, and then use only the name of your file
wb = openpyxl.load_workbook('example.xlsx')
You may also verify its existence with commands — use copy/paste from your code to avoid typos in the file name / path
import os.path
print(os.path.exists('example.xlsx')) # True, if Python sees it
or
import os.path
print(os.path.exists('C:/users/John/example.xlsx')) # True, if exists
to be sure that I'm right, i.e. that the error is not in the function openpyxl.load_workbook() itself, but in its parameter (the path to the file) provided by you.
I notice that the extension of the example file is not the same as described in the book, is example.csv. I was facing the same frustration as you
Related
Hi I have a beginner problem. So I wanted to access csv file with jupyter notebook and I am using python. I am opening the jupyter notebook on visual studio code. So here is my code
import pandas as pd
df3 = pd.read_csv("D:/medali.csv")
imax = df3["bronze"].idxmax()
df3[imax:imax+1]
The thing is I kept stuck with the error
FileNotFoundError: [Errno 2] No such file or directory: 'D:/medali.csv'
I assume it is due to pathway problem so I've put the .ipynb file with the .csv file in one folder but it does not work. How to solve the error?
The easiest thing to do, assuming you're on windows os, is to go to the file, right click, select "copy as file path", and then put that in the place of "D:/medali.csv". That should fix the issue, but you may find that you also have to set the file path string as a raw string to keep it from being messed up by the \ or / characters that windows uses. To do this, type a single "r" in front of the file path string, without the quotations. Just the character "r".
Another thought to try is that you may need to actually "Open" the file first, and then try to read from it. Given that you're in python, I would recommend the following syntax:
import pandas as pd
with open(r"filepath.csv", "r") as f:
df3 = pd.read_csv("D:/medali.csv")
imax = df3["bronze"].idxmax()
df3[imax:imax+1]
This is best practice because when you open the file with the "with" keyword, it will close after the block under it has executed automatically.
I am trying to rename a file, but python cannot find the file specified.
I have a file located here:
C:\Users\my_username\Desktop\selenium_downloads\close_of_day_reports\close-of-day-2022-04-24-2022-04-23.pdf
I am trying to rename the file to test.pdf
Here is the code I am using:
import os
os.rename(
src = "C:\\Users\\my_username\\Desktop\\selenium_downloads\\close_of_day_reports\\close-of-day-2022-04-24-2022-04-23.pdf",
dst = "C:\\Users\\my_username\\Desktop\\selenium_downloads\\close_of_day_reports\\test.pdf"
)
The error message I am getting is:
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'C:\\Users\\my_username\\Desktop\\selenium_downloads\\close_of_day_reports\\close-of-day-2022-04-24-2022-04-23.pdf' ->
'C:\\Users\\my_username\\Desktop\\selenium_downloads\\close_of_day_reports\\test.pdf'
What am I doing wrong?
Edit #1:
The original file was not deleted, it still exists.
It's really strange, when I run it the first time, the file does not get renamed, but when I run it again, it does.
Weird, for some reason it works in Python Shell, but not my Python file.
Edit #2:
I am using Selenium to download the file. When I comment the part of my code out that downloads the file from Selenium, my os.rename code works fine. Weird.
Based off the error, I think you are still leaving one the original name or not changing the right one.
import os
os.rename(
src = "C:\\Users\\my_username\\Desktop\\selenium_downloads\\close_of_day_reports\\test.pdf",
dst = "C:\\Users\\my_username\\Desktop\\selenium_downloads\\close_of_day_reports\\close-of-day-2022-04-24-2022-04-23.pdf"
)
I'm pretty sure you ran the code once, renamed the file, and now it won't run again because you already renamed it.
Careful reading is your friend. Computers don't know or care what you meant:
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'C:\Users\my_usernamer\Desktop\selenium_downloads\close_of_day_reports\close-of-day-2022-04-24-2022-04-23.pdf'
See the stray r in the path?
Found the solution:
When you download files using Selenium, you need to put in a sleep method for a few seconds and then you can download/move files without a problem.
Put this in your code after downloading the file, before downloading another:
from time import sleep
sleep(10)
pass
You may need to increase the sleep value, but 10 worked for me. The number inside of sleep represents seconds, so sleep(10) means to wait 10 seconds.
I'm trying to store a pandas dataframe to a tempfile in csv format (in windows), but am being hit by:
[Errno 13] Permission denied: 'C:\Users\Username\AppData\Local\Temp\tmpweymbkye'
import tempfile
import pandas
with tempfile.NamedTemporaryFile() as temp:
df.to_csv(temp.name)
Where df is the dataframe. I've also tried changing the temp directory to one I am sure I have write permissions:
tempfile.tempdir='D:/Username/Temp/'
This gives me the same error message
Edit:
The tempfile appears to be locked for editing as when I change the loop to:
with tempfile.NamedTemporaryFile() as temp:
df.to_csv(temp.name + '.csv')
I can write the file in the temp directory, but then it is not automatically deleted at the end of the loop, as it is no longer a temp file.
However, if I change the code to:
with tempfile.NamedTemporaryFile(suffix='.csv') as temp:
training_data.to_csv(temp.name)
I get the same error message as before. The file is not open anywhere else.
I encountered the same error message and the issue was resolved after adding "/df.csv" to file_path.
df.to_csv('C:/Users/../df.csv', index = False)
Check your permissions and, according to this post, you can run your program as an administrator by right click and run as administrator.
We can use the to_csv command to do export a DataFrame in CSV format. Note that the code below will by default save the data into the current working directory. We can save it to a different folder by adding the foldername and a slash to the file
verticalStack.to_csv('foldername/out.csv').
Check out your working directory to make sure the CSV wrote out properly, and that you can open it! If you want, try to bring it back into python to make sure it imports properly.
newOutput = pd.read_csv('out.csv', keep_default_na=False, na_values=[""])
ref
Unlike TemporaryFile(), the user of mkstemp() is responsible for deleting the temporary file when done with it.
With the use of this function may introduce a security hole in your program. By the time you get around to doing anything with the file name it returns, someone else may have beaten you to the punch. mktemp() usage can be replaced easily with NamedTemporaryFile(), passing it the delete=False paramete.
Read more.
After export to CSV you can close your file with temp.close().
with tempfile.NamedTemporaryFile(delete=False) as temp:
df.to_csv(temp.name + '.csv')
temp.close()
Sometimes，you need check the file path that if you have right permission to read and write file. Especially when you use relative path.
xxx.to_csv('%s/file.csv'%(file_path), index = False)
Sometimes, it gives that error simply because there is another file with the same name and it has no permission to delete the earlier file and replace it with the new file.
So either name the file differently while saving it,
or
If you are working on Jupyter Notebook or a other similar environment, delete the file after executing the cell that reads it into memory. So that when you execute the cell which writes it to the machine, there is no other file that exists with that name.
I encountered the same error. I simply had not yet saved my entire python file. Once I saved my python file in VS code as "insertyourfilenamehere".py to documents(which is in my path), I ran my code again and I was able to save my data frame as a csv file.
As per my knowledge, this error pops up when one attempt to save the file that have been saved already and currently open in the background.
You may try closing those files first and then rerun the code.
Just give a valid path and a file name
e.g:
final_df.to_csv('D:\Study\Data Science\data sets\MNIST\sample.csv')
I'm trying to load a .csv file using the pd.read_csv() function when I get an error despite the file path being correct and using raw strings.
import pandas as pd
df = pd.read_csv('C:\\Users\\user\\Desktop\\datafile.csv')
df = pd.read_csv(r'C:\Users\user\Desktop\datafile.csv')
df = pd.read_csv('C:/Users/user/Desktop/datafile.csv')
all gives the error below:
FileNotFoundError: File b'\xe2\x80\xaaC:/Users/user/Desktop/tutorial.csv' (or the relevant path) does not exist.
Only when i copy the file into the working directory will it load correct.
Is anyone aware of what might be causing the error?
I had previously loaded other datasets with full filepaths without any problems and I'm currently only encountering issues since I've re-installed my python (via Anaconda package installer).
Edit:
I've found the issue that was causing the problem.
When I was copying the filepath over from the file properties window, I unwittingly copied another character that seems invisible.
Assigning that copied string also gives an unicode error.
Deleting that invisible character made any of above code work.
Try this and see if it works. This is independent of the path you provide.
pd.read_csv(r'C:\Users\aiLab\Desktop\example.csv')
Here r is a special character and means raw string. So prefix it to your string literal.
https://www.journaldev.com/23598/python-raw-string:
Python raw string is created by prefixing a string literal with ‘r’
or ‘R’. Python raw string treats backslash () as a literal character.
This is useful when we want to have a string that contains backslash
and don’t want it to be treated as an escape character.
$10 says your file path is correct with respect to the location of the .py file, but incorrect with respect to the location from which you call python
For example, let's say script.py is located in ~/script/, and file.csv is located in ~/. Let's say script.py contains
import pandas
df = pandas.read_csv('../file.csv') # correct path from ~/script/ where script.py resides
If from ~/ you run python script/script.py, you will get the FileNotFound error. However, if from ~/script/ you run python script.py, it will work.
I know following is a silly mistake but it could be the problem with your file.
I've renamed the file manually from adfa123 to abc.csv. The extension of the file was hidden, after renaming, Actual File name became abc.csv.csv. I've then removed the extra .csv from the name and everything was fine.
Hope it could help anyone else.
import pandas as pd
path1 = 'C:\\Users\\Dell\\Desktop\\Data\\Train_SU63ISt.csv'
path2 = 'C:\\Users\\Dell\\Desktop\\Data\\Test_0qrQsBZ.csv'
df1 = pd.read_csv(path1)
df2 = pd.read_csv(path2)
print(df1)
print(df2)
On Windows systems you should try with os.path.normcase.
It normalize the case of a pathname. On Unix and Mac OS X, this returns the path unchanged; on case-insensitive filesystems, it converts the path to lowercase. On Windows, it also converts forward slashes to backward slashes. Raise a TypeError if the type of path is not str or bytes (directly or indirectly through the os.PathLike interface).
import os
import pandas as pd
script_dir = os.getcwd()
file = 'example_file.csv'
data = pd.read_csv(os.path.normcase(os.path.join(script_dir, file)))
If you are using windows machine. Try checking the file extension.
There is a high possibility of file being saved as fileName.csv.txt instead of fileName.csv
You can check this by selecting File name extension checkbox under folder options (Please find screenshot)
below code worked for me:
import pandas as pd
df = pd.read_csv(r"C:\Users\vj_sr\Desktop\VJS\PyLearn\DataFiles\weather_data.csv");
If fileName.csv.txt, rename/correct it to fileName.csv
windows 10 screen shot
Hope it works,
Good Luck
Try using os.path.join to create the filepath:
import os
f_path = os.path.join(*['C:', 'Users', 'user', 'Desktop', 'datafile.csv'])
df = pd.read_csv(f_path)
I was trying to read the csv file from the folder that was in my 'c:\'drive but, it raises the error of escape,type error, unicode......as such but this code works
just take an variable then add r to read it.
rank = pd.read_csv (r'C:\Users\DELL\Desktop\datasets\iris.csv')
df=pd.DataFrame(rank)
There is an another problem on how to delete the characters that seem invisible.
My solution is copying the filepath from the file windows instead of the property windows.
That is no problem except that you should fulfill the filepath.
Experienced the same issue. Path was correct.
Changing the file name seems to solve the problem.
Old file name: Season 2017/2018 Premier League.csv
New file name: test.csv
Possibly the whitespaces or "/"
I had the same problem when running the file with the interactive functionality provided by Visual studio. Switched to running on the native command line and it worked for me.
For my particular issue, the failure to load the file correctly was due to an "invisible" character that was introduced when I copied the filepath from the security tab of the file properties in windows.
This character is e2 80 aa, the UTF-8 encoding of U+202A, the left-to-right embedding symbol. It can be easily removed by erasing (hitting backspace or delete) when you've located the character (leftmost char in the string).
Note: I chose to answer because the answers here do not answer my question and I believe a few folks (as seen in the comments) might meet the same situation as I did. There also seems to be new answers every now and then since I did not mark this question as resolved.
I had similar problem when I was using JupyterLab + Anaconda, and used my browser to type stuff on IDE.
My problem was simpler - there was a very subtle typo error. I didn't have to use raw text - either escaping or using {{r}} string worked for me :). If you use Anaconda with Jupyter Lab, I believe the Kernel starts with where you open the notebook from i.e. the working directory is that top level folder.
data = pd.read_csv('C:\\Users\username\Python\mydata.csv')
This worked for me. Note the double "\\" in "C:\\" where the rest of the folders use only a single "\".
I have a rather simple program that writes HTML code ready for use.
It works fine, except that if one were to run the program from the Python command line, as is the default, the HTML file that is created is created where python.exe is, not where the program I wrote is. And that's a problem.
Do you know a way of getting the .write() function to write a file to a specific location on the disc (e.g. C:\Users\User\Desktop)?
Extra cool-points if you know how to open a file browser window.
The first problem is probably that you are not including the full path when you open the file for writing. For details on opening a web browser, read this fine manual.
import os
target_dir = r"C:\full\path\to\where\you\want\it"
fullname = os.path.join(target_dir,filename)
with open(fullname,"w") as f:
f.write("<html>....</html>")
import webbrowser
url = "file://"+fullname.replace("\\","/")
webbrowser.open(url,True,True)
BTW: the code is the same in python 2.6.
I'll admit I don't know Python 3, so I may be wrong, but in Python 2, you can just check the __file__ variable in your module to get the name of the file it was loaded from. Just create your file in that same directory (preferably using os.path.dirname and os.path.join to remain platform-independent).